A circle is centered at 7,8 and has a radius of 11 what is the equation?

ANSWERS

2015-11-07 01:55:21

SchwarzschildRadius here: So, The equation for a circle is: [latex](x-h)^2+(y-k)^2=r^2[/latex] Where the center of the circle is (h,k), and the radius of the circle is r. Substituting 7,8 for (h,k) and 11 for r in the equation gives us: [latex](x-7)^2+(y-8)^2=11^2[/latex] That would be standard form. Hope this helps!

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