What is the length and width of a room that is 60 square meters and has a perimeter of 32 meters

ANSWERS

2015-11-06 21:36:56

L = lenght W = width [latex]L * W = 60 \ 2L + 2W=32\\ L = frac{32-2W}{2}\ frac{32-2W}{2}*W = 60\ (16-W)*W = 60\ -W^{2} + 16W -60 = 0\\ d = 16^{2} - 4*1*60 = 256 - 240 = 16 \\ W1 = frac{-16+sqrt{16}}{-2} = frac{-12}{-2} = 6\ W2 = frac{-16-sqrt{16}}{-2} = frac{-20}{-2} = 10\ L1 = 10\ L2 = 6\ [/latex] so {L,W} = {6,10} or {10,6} but L > W so L = 10 W = 6

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