The perimeter of a rectangle is 32 feet. The length is 6 more than the width. What are the dimensions of the table?

ANSWERS

2015-11-06 11:52:25

P=2(L+W) 32=P 32=2(L+W) divide by 2 both sides 16=L+W length is 6 more than width L=6+W subsisute 6+W for length in other equation 16=L+W 16=6+W+W 16=6+2W minsu 6 both sides 10=2W divide both sides by 2 5=W sub back L=6+W L=6+5 L=11 the length is 11ft the width is 5ft

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