In the diagram, which must be true for point D to be an orthocenter?
BE, CF, and AG are angle bisectors.
BE ⊥ AC, AG ⊥ BC, and CF ⊥ AB.
BE bisects AC, CF bisects AB, and AG bisects BC.
BE is a perpendicular bisector of AC, CF is a perpendicular bisector of AB, and AG is a perpendicular bisector of BC.
Please help!!!

ANSWERS

2016-09-24 17:13:14

A copy of the diagram is shown below Point D is the intersection of three angle bisector. BE is the angle bisector of ∠B CF is the angle bisector of ∠C AG is the angle bisector of ∠A Point D is also the intersection between three perpendicular bisector BE is the perpendicular bisector of AC AG is the perpendicular bisector of BC CF is the perpendicular bisector of AB Hence the correct statements is statement 1 and statement 4

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