Peter walks 3 minutes at a constant rate and travels 330 meters. If we graph this relationship with time along the x-axis and distance along the y-axis, the slope of the line representing this relationship is

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2016-09-24 00:51:14

The graph of the journey is shown in the speed-time graph below At the time = 3 minutes, Peter would have achieved the speed V. The distance he travelled is the area under the line as shown in the graph We first need to find the V by using the area of a rectangle formula [latex]Area= frac{(b)(h)}{2} [/latex] [latex]330= frac{3h}{2} [/latex] [latex]660=3h[/latex] [latex]h=660/3=220[/latex] so V=220 the gradient the f slope then given as [latex] frac{220}{3} [/latex]

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